STP? Chemistry help...........?
1030.4 mL of C2H6 gas at STP = ? grams
I have an idea about how to do this but I dont think its right, so if anyone could help that would be amazing!
- HarleyLv 58 years agoFavorite Answer
Ideal gas law:
PV = nRT
Where P is pressure, V is volume, n is moles of gas,
R is gas constant, and T is temperature
n = PV/ RT
Conditions of STP:
273 Kelvin, 101.3 kPa
n = (101.3kPa)(1.0304L)/ (8.314 L - kPa/ K*mol)(273K)
n = 0.04599 moles C2H6
Convert to grams:
0.04599 moles x 30.069g/ mol = 1.383 grams C2H6 at STP