## Trending News

# what does not represent a rectangle with lengths s+4, width s+8, and area of 75?

A.(s+4)(s+8)-75=0

B.(s+4)(s+8)=75

C. s^2+12s+43=0

D. s^2+12s-43=0

### 3 Answers

- ~ Sazid Asper ~Lv 48 years agoFavorite Answer
Length = s plus 4,

breadth = s plus 8.

So,area = (s plus 4)*(s plus 8)

= s^2 plus 12s plus 32.

Now,this one equals to 75.

Now,

A. (s 4)(s 8)-75=0

It represents the rectangle.Because,

Area of the rectangle = (s plus 4) * (s plus 8) = 75.

Or, (s plus 4) * (s plus 8) - 75 = 0.

Next One,

B.(s 4)(s 8)=75

It also represents the rectangle.Just as choice A.

Next One,

C. s^2 12s 43=0

Earlier we've found that,

s^2 plus 12s plus 32 = 75

So, s^2 plus 12s plus 32 - 75 = 0.

Or, s^2 plus 12s - 43 = 0.

But,here it is plus 43.

Therefore,it DOES NOT represent the rectangle.

And lastly,

D. s^2 12s-43=0

It represents the rectangle.Explained in (C).

So, choice C is the right answer.

- MercyLv 78 years ago
Try each one and see which equation is true.

D. s^2+12s-43=0

(s+...) ( s_...) = 0.....no numbers possible

.............................

A.

(s+4)(s+8)-75=0

s+4 = 0

s + 8 = 0

s= -4, s=-8 ( example of one that works)