what does not represent a rectangle with lengths s+4, width s+8, and area of 75?

A.(s+4)(s+8)-75=0

B.(s+4)(s+8)=75

C. s^2+12s+43=0

D. s^2+12s-43=0

3 Answers

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  • 8 years ago
    Favorite Answer

    Length = s plus 4,

    breadth = s plus 8.

    So,area = (s plus 4)*(s plus 8)

    = s^2 plus 12s plus 32.

    Now,this one equals to 75.

    Now,

    A. (s 4)(s 8)-75=0

    It represents the rectangle.Because,

    Area of the rectangle = (s plus 4) * (s plus 8) = 75.

    Or, (s plus 4) * (s plus 8) - 75 = 0.

    Next One,

    B.(s 4)(s 8)=75

    It also represents the rectangle.Just as choice A.

    Next One,

    C. s^2 12s 43=0

    Earlier we've found that,

    s^2 plus 12s plus 32 = 75

    So, s^2 plus 12s plus 32 - 75 = 0.

    Or, s^2 plus 12s - 43 = 0.

    But,here it is plus 43.

    Therefore,it DOES NOT represent the rectangle.

    And lastly,

    D. s^2 12s-43=0

    It represents the rectangle.Explained in (C).

    So, choice C is the right answer.

  • 8 years ago

    C. s^2+12s+43 = 0 does not

  • Mercy
    Lv 7
    8 years ago

    Try each one and see which equation is true.

    D. s^2+12s-43=0

    (s+...) ( s_...) = 0.....no numbers possible

    .............................

    A.

    (s+4)(s+8)-75=0

    s+4 = 0

    s + 8 = 0

    s= -4, s=-8 ( example of one that works)

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