On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad?

A) On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snohomish River below. The swimmers stepped off the bridge, and they hit the water 1.31 s later. How high was the bridge?

B)How fast were the swimmers moving when they hit the water?

C)What would the swimmer's drop time be if the bridge were twice as high?

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  • 8 years ago
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    Hot summers day? Washington? Are we talking about the same place?

    Didn't the swimmers have to dodge icebergs?

    As s = 1/2 g t^2

    s = 1/2 * 4.9 * 1.31^2 = 4.2 m

    V = gt = 1.31* 9.8 = 12.8 m/s

    if s is proportional to t^2 then t is proportional to the square root of height.

    if H2/H1 = 2 then T2/T1 = sqrt(2)

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