On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad?
A) On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snohomish River below. The swimmers stepped off the bridge, and they hit the water 1.31 s later. How high was the bridge?
B)How fast were the swimmers moving when they hit the water?
C)What would the swimmer's drop time be if the bridge were twice as high?
- Andrew SmithLv 78 years agoFavorite Answer
Hot summers day? Washington? Are we talking about the same place?
Didn't the swimmers have to dodge icebergs?
As s = 1/2 g t^2
s = 1/2 * 4.9 * 1.31^2 = 4.2 m
V = gt = 1.31* 9.8 = 12.8 m/s
if s is proportional to t^2 then t is proportional to the square root of height.
if H2/H1 = 2 then T2/T1 = sqrt(2)