# A car traveled 48 miles west and then 14 miles south. How far is the car from its starting point? _____?

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• 7 years ago

A car traveled 48 miles west and then 14 miles south.

How far is the car from its starting point?

Sqrt (48^2 + 14^2) = sqrt 2500

= 50 miles

• It seems a bit complicated, but it's easier if you sketch out the problem: http://img27.imageshack.us/img27/3091/f63d7833c307...

As you can see by the diagram, the car movements form a right triangle. So we can use the Pythagorean Theorem. (You could also use distance formula, but that's more work) The actual movements made by the car (48 mi and 14 mi) are the legs of the triangle, and the distance that you're trying to find is the hypotenuse.

a^2 + b^2 = c^2

(48)^2 + (14)^2 = c^2

2500 = c^2

50 = c

The car is 50 miles from its starting point. Hope this helps!

• 7 years ago

Use the Pythagorean Theorem.

The displacements you provided are the two shorter sides of a right angle triangle, and the displacement vector you're looking for is the hypotenuse:

magnitude of displacement = square root of (48^2 + 14^2) = 50 miles.

Therefore, your displacement is 50 miles southwest.

• 7 years ago

14^2 + 48^2 = c^2

196 + 2,304 = c^2

2,500 = c^2

c = 50 miles southwest

I hope this information was very helpful.

• zulma
Lv 4
3 years ago

they are correct right here's the way you get it: a^2 + b^2 = c^2 a = horizontal b = vertical c = direct distance to starting up element c^2=40 8^2 + 14^2=2500 sq. miles (the sq. root of that is your answer) 50 miles

• 7 years ago

USE PYTHAGOREAN THEOREM

48^2 + 14^2 = 2304 + 196 = 2500

• 7 years ago

Yes, 50

Source(s): I was lazy and used a website... http://easycalculation.com/trigonometry/triangle-a...
• 7 years ago

50 miles

southwest from it's starting point.