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# a coin has 71% probability of being heads after 6 tosses what is the probability of getting <4 heads?

Please help me solve this, I cant figure out the equation to calculate less than. Thanks!

Update:

Here is exactly how the problem is typed by my professor.

"A crooked coin has a 71% probability of heads, we tossed it 6 times, what is the probability of getting less than 4 heads?

Hope this clarifies. Thank you.

### 3 Answers

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- M3Lv 78 years agoFavorite Answer
binomdist with n = 6, p = 0.71, q = 0.29

P[x<4] = sum of C(6,x) *0.71^x *0.29^(6-x) for x = 0 to 3

= 0.2374

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- NoneLv 78 years ago
Unclear problem statement. Do you mean that the probability derived from 6 tosses of a head is 71%?

- Anonymous6 years ago
tricky task seek at yahoo just that may help

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