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# the quadratic formula for 5x^2+33x+40?

im stuck on cognitive tutor ;-;

### 3 Answers

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- ranjankarLv 78 years agoFavorite Answer
5x^2 +33x = -40

DIVIDE BY 5

x^2 + 33/5x = -8

ADD 1089/100

x^2 + 33/5x +1089/100 = 1089/100 -8 = 289/100

( x + 33/10 )^2 = 289/100

x = 1/10 ( -33 +17) OR 1/10 ( -33 -17)

x = -8/5 OR -5 ANSWER

- NiallLv 78 years ago
x = [-b ± √b² - 4ac]/2a

x = [-33 ± √(33)^2 - 4(5)(40)] / (2)(5)

x = [-33 ± √1089 - 800] / 10

x = [-33 ± √289] / 10

x = [-33 ± 17] / 10

Now solve for each:

x = -16/10 (simplifies to -8/5)

x = -50/10 (simplifies to -5)

x = -5, -8/5

- 8 years ago
x = [-b+/-sqrt(b^2-4ac)]/2a

x = [-33+/-sqrt(33^2 - 4(5)(40))]/2(5)

x = [-33+/-sqrt(1089-800)]/10

x = [-33+/-sqrt(289]/10

x = (-33 +/- 17)/10

x = (-33+17)/10, (-33-17)/10

x = -16/10, -5

x = -1 3/5, -5

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