a IRS auditor randomly selects 3 tax returns from 50 returns of which 20 contain errors. what is the?

probability that she selects NONE of those containing errors?

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  • Anonymous
    8 years ago
    Favorite Answer

    50/50.

  • 8 years ago

    I think this is a permutation.

    Odds of the first not containing an error = 3/5

    Second = 29/49

    Third = 28/48

    Multiply each together to get roughly a 21% chance.

  • 8 years ago

    20/50 * 19/49 * 18/48 = 0.058163

  • 4 years ago

    whats up, possibility that she will have the ability to get none potential she needs to get a suitable run from the beginning up: (fifty two/fifty seven)*(fifty one/fifty six)*(50/fifty 5)=1105/1463. seventy 5.529733%... in this sort we nonetheless get 5 in those returns, yet none choosen.

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