a IRS auditor randomly selects 3 tax returns from 50 returns of which 20 contain errors. what is the?
probability that she selects NONE of those containing errors?
- Anonymous8 years agoFavorite Answer
- Re VeraLv 78 years ago
I think this is a permutation.
Odds of the first not containing an error = 3/5
Second = 29/49
Third = 28/48
Multiply each together to get roughly a 21% chance.
- kelby7670Lv 78 years ago
20/50 * 19/49 * 18/48 = 0.058163
- 4 years ago
whats up, possibility that she will have the ability to get none potential she needs to get a suitable run from the beginning up: (fifty two/fifty seven)*(fifty one/fifty six)*(50/fifty 5)=1105/1463. seventy 5.529733%... in this sort we nonetheless get 5 in those returns, yet none choosen.