What is the Pressure inside the container?

A cook puts 5.80 g of water in a 2.00-L pressure cooker that is then warmed to 480°C. What is the pressure inside the container? (Assume room temperature is 20°C.)

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  • 8 years ago
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    (2.00 L) x (273 / (20 + 273)) / (22.414 L/mol) = 0.083139 mol air in the "empty" container

    (5.80 g H2O) / (18.01532 g H2O/mol) = 0.32195 mol H2O added

    Supposing all the water vaporized:

    PV = nRT

    P = nRT / V = (0.083139 mol + 0.32195 mol) x (0.08205746 L atm/K mol) x

    (480 + 273 K) / (2.00 L) = 12.5 atm

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