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# convert to polar notation and multiply?

(2√(3)-2i)(2-2i)

show me the work please.

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- Anonymous8 years agoFavorite Answer
Converting into Polar Coordinates we have;

(2√(3)-2i), which has magnitude 4 and argument 11*pi/6 => Polar form 4*e^(i*11*pi/6)

(2-2i), has magnitude, 2sqrt(2) and argument 7*pi/4 => Polar form 2sqrt(2)*e^(i*7*pi/4)

Multiplying them together we get 8sqrt(2)e^(i*19*pi/12)

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