how fast (in m/s) will a freely falling stone be moving on the moon 2 seconds after it is dropped from rest?

if the acceleration due to gravity of the moon is 1/6 the value on earth., how fast (in m/s) will a freely falling stone be moving on the moon 2 seconds after it is dropped from rest?

3 Answers

Relevance
  • 8 years ago
    Favorite Answer

    The gravity on the moon is 1.6 (we divided 9.6 the normal gravity on earth by 6)

    time = 2seconds

    u= 0 because it is starting from rest

    We are looking for the speed so v will represent that

    Use this formula- v= u + gt

    so...

    v = (0)+(1.6)(2)

    v=3.2 ms-1

  • simer
    Lv 4
    4 years ago

    It does no longer by way of fact the gravity of the earth out training that of the moon so purely the moon could desire to fall onto the earth, and it could fall as quickly as something that's falling 362 ft in line with 2d i think of, or some thing like that, yet what could in all probability be extra important is that the consequent result could be sufficient to crack better than 1 / 4 of our planet off. Many scientists have faith the moon broke off of the earth in the process the photograph voltaic systems primordial stages by utilising asteroid result.

  • 8 years ago

    BY v = u + gt

    =>v = 0 + (9.8/6) x 2

    =>v = 3.27 m/s

Still have questions? Get your answers by asking now.