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# let f(x) = log3 x/2 + log3 16 - log3 4 for x>0?

a. show that f(x) = log 3 2x.

b. find the value of f(0.5) and of f(4.5)

The junction f can also be written in the form f(x)=ln ax/ln b

c. i. Write down the value of a and of b

ii. write down the equation of the asymptote.

d. write down the value of f-1(o)

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- tcLv 78 years ago
f(x) = log₃ x/2 + log₃ 16 - log₃ 4

= log₃(x/2 * 16 /4)

= log₃(2x)

f(0.5) = log₃(1) = 0

f(4.5) = log₃(9) = log₃ 3² = 2

f(x)=ln ax/ln b = ln 2x / ln 3

a = 2

b = 3

VA : x = 0

f-1(0)

=> 0 = log₃(2x)

3⁰ = 2x = 1

x = 1/2

⁰

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