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# Find the absolute maximum and absolute minimum values of f on the given interval.?

f(x) = ln(x^2 + 7x + 14), [−4, 1]

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- Anonymous8 years agoFavorite Answer
Differentiate the function to get...

f'(x) = (2x + 7)/(x² + 7x + 14)

So?

0 = 2x + 7

x = -7/2

Therefore...

f(-4) ≈ 0.693

f(1) ≈ 3.09 [max]

f(-7/2) ≈ 0.560 [min]

Good luck!

Source(s): τ

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