saturated solution of barium fluoride has [Ba2+] = 6.3 x 10-3 M. What is the Ksp for barium fluoride?
I have no idea how to do this. Please help :(
- JOHLv 68 years agoFavorite Answer
[Ba^2+] = 6.3x10^-3 M
[F^-] = 2 x [Ba^2+] = (2)(6.3x10^-3) = 1.26x10^-2 M
Ksp = [Ba^2+][F^-]^2 = (6.3x10^-3)(1.26x10^-2)^2 = 1.0x10^-6
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