X varies inversely as Y^2, if X=2 when Y=8, what's Y when X=7?

I know the first part, K=128. It's the second part I'm having trouble with....?

Update:

L.E. Grant, should the final answer 128/7 be inside a radical because of the Y^2?

3 Answers

Relevance
  • 8 years ago
    Favorite Answer

    X=k/Y^2

    k=128

    7=128/Y^2

    Y^2 x 7=128

    Y^2 =128/7

    Y=sqrt(128/7)

  • 8 years ago

    xy^2 = k...

    so 2 * 64 = 7 * y

    ==> y = 128/7

  • Anonymous
    4 years ago

    it appears like one to me. yet it somewhat is in simple terms proportionally. for all all people comprehend, there is like a conic equation or quadratic or some thing on the decrease back of the question. yet proportionally, the respond is one million.

Still have questions? Get your answers by asking now.