MATH HELP ! SOLVING WITH ELIMINATION ! NON- STANDARD FORM?

6x - 6y + 8 = 14

8y = 4x + 4

3 Answers

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  • M3
    Lv 7
    8 years ago
    Favorite Answer

    first convert it to standard form

    6x - 6y = 6

    or x - y = 1 ......(i)

    4x -8y = -4

    or x - 2y = -1 .....(ii)

    (i) - (ii)

    y = 2

    substitute in (i)

    x = 3

    ans: (3,2)

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  • 8 years ago

    The first thing to do is to get the equations into standard form:

    6x -6y = 6

    -4x + 8y = 4

    divide out the 6 from the first equation and divide the second equation by 4. You will then have:

    x - y = 1

    -x + 2y = 1

    Add the two equations. the x's cancel out and you have:

    2y - y = 2

    y = 2

    substitute y=2 into the first equation to get

    x - 2 = 1

    x = 3

  • Kate
    Lv 4
    8 years ago

    6x - 6y = 6 (1)

    4x - 8y = -4 (2)

    (1) x 4:

    24x - 24y = 24 (3)

    (2) x 6:

    24x - 48y = -24 (4)

    (3) - (4):

    24y = 48

    y = 2

    Substitute y = 2 into (1):

    6x - 12 = 6

    6x = 18

    x = 3

    Therefore x = 3 and y = 2.

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