math help ! solving elimination in non standard form!!?

Question

9x - 3y = 63

7x - 3y = 45

Answer 1

9x - 3y = 63

7x - 3y = 45.........Multiply by - 1

9x - 3y = 63

-7x + 3y = -45

*****************ADD

2x = 18

x = 9

9(9) - 3y = 63

81 - 3y = 63

-81........- 81

- 3y = - 18

y = 6

( 9 , 6 ) ......................ANSWER

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Answer 2

9x-3y=63

7x-3y=45

9x-3y=63

-7x=3y=-45

(-3y and +3y gets canceled and the rest we solve it)

it becomes:-

2x= 18

then,

x=18/2=9

therfore,

x=9

to find y(substitute the value of x in any one eq.)

7x-3y=45

7(9)-3y=45

63-3y=45

-3y=-18

y=6

therefore the value of:

x=9 , y=6

Answer 3

9x - 3y = 63 ........eq1

7x - 3y = 45 .........eq2

-----------------------------

2x = 18 ..............eq1 - eq2

x = 9 ..................................... x solved

9x - 3y = 63 ........eq1

81 - 3y = 63

-3y = 63 - 81 = -18

y = 6 ....................................... y solved

check:

7x - 3y = 45 .........eq2

7*9 - 3*6 = 45

63 - 18 = 45 ........................ true!!!

Our answer is:

(x,y) = (9, 6)

.......

Answer 4

9x - 3y = 63

-7x + 3y = - 45______ADD

2x = 18

x = 9

63 - 3y = 45

18 = 3y

y = 6

x = 9 , y = 6

Answer 5

-1 (9x-3y=63

7x-3y=45

-9x+3y=-63

7x-3y=45

--------------

-2x=-18

x=9 if x=9 y=6

Answer 6

9x - 3y = 63

7x - 3y = 45

------------------ (subtract)

2x = 18

x = 9

and if x =9, then 9(9) - 3y = 63

81 - 63 = 3y

18 = 3y

y = 6

(9 , 6) = (x , y)

check in the other equation:

7(9) - 3(6) = 63 - 18 = 45 checks

Answer 7

the 1st ingredient to do is to get the equations into familiar variety: 6x -6y = 6 -4x + 8y = 4 divide out the 6 from the 1st equation and divide the 2nd equation through four. you will then have: x - y = a million -x + 2y = a million upload the two equations. the x's cancel out and you have: 2y - y = 2 y = 2 exchange y=2 into the 1st equation to get x - 2 = a million x = 3