How to find tangent lines to the inflection pts of a function?
Say we f(x)=x^4 - 6x^3 + 12x^2
f'(x)= 4x^3 - 18x^2 + 24x
f''(x) = 12x^2 - 36x + 24
so the inflection pts are x = 2, x = 1.
Now what do I do to get the tangent lines?
- RayLv 78 years agoFavorite Answer
At points of inflection the gradient of the tangent lines are zero, that is the tangent is a line parallel to the x axis.
So if we know x = 2 and x = 1 then simply work out f(2) and f(1).
f(2) = 16
f(1) = 7
Thus the tangent lines at the points of inflection are y = 16 and y = 7.