Fusion of Deuterium Nuclei?

Fusion of two deuterium nuclei to form helium-3 and hydrogen -1 yields 1.53 x 10(-16)kcal of energy. A liter of seawater is estimated to contain 1.03 x 10(22) atoms of deuterium. How many kilocalories can be liberated if all the 1.03 x 10(22) deuterium atoms in a liter of seawater undergo fusion?

Can anyone help?!? Thank you!

1 Answer

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  • Iggy
    Lv 7
    8 years ago
    Favorite Answer

    This is a simple problem of scale.

    Given 1.03 * 10^22 atoms that liberate 1.53 * 10^-16 kCal then if all the atoms reacted you would liberate 1.03 * 10^22 * 1.53 * 10^-16 kCal ~ 1.58 * 10^6 kCal.

    Enjoy :)

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