Domain and range of f(x) = cube root x?

The answer is the set of real numbers, right? WolframAlpha gives x>=0 and y>=0, and I can't figure out why it gives this result.

http://www.wolframalpha.com/input/?i=domain+and+ra...

3 Answers

Relevance
  • 8 years ago
    Favorite Answer

    Windows calculator, too, gives error when trying to get cube root of (-8) as well as my calculator

    and Wolfram Alpha, too

    http://www.wolframalpha.com/input/?i=cube+root+-8

    but ∛(-8) = - 2, as we all know since middle school

    the reason why calculators and Wolfram give error is that domain and of x^y is assumed to be R+ (0 excluded)

    it is a good reason because if in x^y you let x to be negative, each rational exponent with even denominator would not exist in R!

    Anyway x^3 is invertible on R, therefore

    domain and range of cube root are R

  • 4 years ago

    Wolfram Alpha Domain And Range

  • 8 years ago

    The square root of a negative number is undefined, therefore the range is y>0 for f(x)= square root x. But the cubed root of a negative number is a real number, so the graph ends up reflecting over the origin making the domain and range all real numbers

Still have questions? Get your answers by asking now.