please help me with this chemistry question please?
what mass of CuSO4 5H2O will be formed when excess Copper II Oxide reacts with 100cm3 of 0.2 mole per dm3 Sulphuric acid?
- hcbiochemLv 78 years agoFavorite Answer
CuO + H2SO4 --> CuSO4 + H2O
Since H2SO4 is your limiting reactant:
moles H2SO4 = 0.100 dm^3 X 0.2 mol/dm = 0.02 mol H2SO4
Moles CuSO4 formed = 0.02 mol
Calculate the molar mass of CuSO4*5H2O, and multiply that by 0.02 mol to get the mass of the hydrate formed.