please help me with this chemistry question please?

what mass of CuSO4 5H2O will be formed when excess Copper II Oxide reacts with 100cm3 of 0.2 mole per dm3 Sulphuric acid?

1 Answer

  • 8 years ago
    Favorite Answer

    Balanced equation:

    CuO + H2SO4 --> CuSO4 + H2O

    Since H2SO4 is your limiting reactant:

    moles H2SO4 = 0.100 dm^3 X 0.2 mol/dm = 0.02 mol H2SO4

    Moles CuSO4 formed = 0.02 mol

    Calculate the molar mass of CuSO4*5H2O, and multiply that by 0.02 mol to get the mass of the hydrate formed.

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