What is the radius(r)of the path for a singly charged ion?
The electric field between the plates of the velocity selector is 2800 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0960 T. Calculate the radius r of the path for a singly charged ion with mass m = 2.79 10-26 kg.
- JánošíkLv 77 years agoFavorite Answer
r = (m × E) / (q × B²)
r = radius = ?
m = mass of the ion = 2.79E-26 kg
E = electric field = 2800 V/m
q = charge of 1 electron = 1.6E-19 C
B = magnetic field = 0.096 T
r = (2.79E-26 × 2800) / (1.6E-19 × 0.096²)
r = 0.05297 m = 5.3 cm