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# solve the equation: with work and answer please?

( 200/(1+99e^(-0.3t) )=50

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- Amar SoniLv 78 years agoFavorite Answer
( 200/(1+99e^(-0.3t) )=50

200/50 = (1+99e^(-0.3t) )

4 = 1+99e^(-0.3t)

3/99 = e^(-0.3t)

1/33 = e^(-0.3t)

33 = e^(0.3t)

ln 33 =0.3 t

t = ln33/0.3 = 11.6550252048883333333 ............Ans

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