What wavelength of light in nm is emitted when the electron in He^+ falls from n = 3 to n = 1?
- Anonymous8 years agoFavorite Answer
Use the Rydberg Equation
1/wavelength = 1.096776 x 10^7 m^(-1) (1/(1^2) - 1/(3^2))
This simplifies to: 1/wavelength = 9749120
Therefore the wavelength is 0.000000103 m, or 103 nm.
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