# How to solve this algebra II problem (solving systems of linear equations in 3 variables)?

Which values should be given to a, b, and c so that the linear system shown has (-1, 2, -3) as its only solution?

x + 2y - 3z = a

- x - y + z = b

2x + 3y - 2z = c

thanks in advance! ♥

x + 2y - 3z = a

- x - y + z = b

2x + 3y - 2z = c

thanks in advance! ♥

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