Jimmy asked in Science & MathematicsMathematics · 7 years ago

# Algebra Word Problems?

Help on the heading and equation.

1) George paid \$1.50 each for programs to the play. He sold all but 30 of them for \$4 each and made a profit of \$30. How many programs did he buy?

2) John had eight more quarters than he did dimes. If the coins were worth \$5.50, how many quarters did he have?

3) Jose has 37 coins (all nickels, dimes, and quarters) worth \$4.70. He has 7 more nickels than dimes. How many quarters does he have?

4) Tom has twice as many dimes as nickels. If he has \$4.50 in coins, how many dimes does he have?

Relevance
• 7 years ago

1) Let the no of programs he bought be x

Total amount spent = 1.50x \$

Sold = ( x-30)

Sale price = 4\$ each

Total sales = ( x-30)*4 = 4x - 120 \$

(4x- 120) - 1.50x = 30

2.5x - 120 = 30

2.5x = 150

x = 150/2.5 = 60 programs ANSWER

CHECK

60 X 1.5 = 90\$

30 X 4 = 120 \$

120-90 = 30\$

2) Dimes = x

Quarters = x+8

Value = 0.10x + 0.25( x+8) = 5.50

0.10x + 0.25x + 2 = 5.50

0.35x = 3.50

x = 10

ANSWER 10 dimes and 18 quarters

CHECK

10 X 0.10 = 1.00

18 X 0.25 = 4.50

3) Dimes = x

Nickels = x+7

Quarters = 37 - ( x + x+7) = 30- 2x

Value = 0.10x + 0.05( x+7) + 0.25 ( 30- 2x) = 4.70

0.10x + 0.05x + 0.35 + 7.50 - 0.5x = 4.70

0.35x = 3.15

x = 9

ANSWER 9 dimes 16 nickels and 12 quarters

CHECK

9 X 0.10 = 0.90

16 X 0.05 =0.80

12 X 0.25 = 3.00

4) Nickels = x

Dimes = 2x

Value 0.05x + 0.10*2x = 4.50

0.25x = 4.50

x = 18

CHECK

18 X 0.05 = 0.90

36 X 0.10 = 3.60