If you needed to prepare 1.99 liters of a 0.55 M solution of NaOH, how many grams of NaOH do you need?

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  • 7 years ago
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    MV = mass / molar mass

    (0.55 mol/L) (1.99 L) = x / 40.0 g/mol

    x = 43.78 g

    Rounded off to two sig figs, 44 g

    Source(s): ChemTeam
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