If you needed to prepare 1.99 liters of a 0.55 M solution of NaOH, how many grams of NaOH do you need?
- ChemTeamLv 77 years agoFavorite Answer
MV = mass / molar mass
(0.55 mol/L) (1.99 L) = x / 40.0 g/mol
x = 43.78 g
Rounded off to two sig figs, 44 gSource(s): ChemTeam
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