Determine the number of oxygen atoms in C6H2CH3(NO3)3?

Determine the number of oxygen atoms in C6H2CH3(NO3)3?

I'm very new to chemistry, so if someone could help me with this problem, I'd be so grateful! <3 Also, how you solved it? Thank you in advance!

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  • 8 years ago
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    Let's see. There are 3 oxygens in that nitrate group (NO3), and there are 3 nitrate groups (NO3)3. 3 x 3 is 9. The answer is nine oxygen atoms in this molecule.

    Source(s): I also teach physics.
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  • 8 years ago

    There are 9 oxygen atoms. The oxygen is represented by O. The NO3 of (NO3)3 part shows that 3 oxygens are bonded to a N atom. The 3 outside the parentheses shows that there are 3 separate NO3 groups. So: 3 times 3 is 9

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  • 8 years ago

    just count the O and apply multiplicity rule for brackets.

    O3*3=9 Oxygen atoms.

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  • 8 years ago

    9

    (NO3)3 means you have 3 NO3's so 9 oxygens/molecule

    http://www.kentchemistry.com/links/GasLaws/molarma...

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  • 3 years ago

    Silver Sulfate, Ag2SO4. a million mole is Avagadro's style (6.022 x 10^23) molecules. with the help of definition .698 mole is .698 x 6.022 x 10^23 = 4.20 x 10^23 with the help of math There are 4 atoms of O in step with molecule of Ag2SO4. with the help of formula consequently, there are (4.20 x 10^23) x 4 atoms = a million.sixty 8 x 10^24 atoms. with the help of math

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