How many mLs are needed in this titration?

In a titration of 35.00 mL of .737 M H2SO4, how many mL of a .827 M KOH solution is required for neutralization?

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  • Anonymous
    8 years ago
    Favorite Answer

    M1V1=M2V2

    .737M*.035L=.827M*V2

    (.737M*.035L)/.827M=V2

    31.2mL=V2

    there you go

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