Bisection Method for quadratic?

! want to do a bisection method for the quadratic (x-1)(x+10)

but the problem is, what two possible numbers and its midpoint

should i used to make a start so that i can get a correct answer??

1 Answer

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  • 9 years ago
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    you need two values that have opposite signs. just try some values:

    how about x=0 and x=3

    f(0)=-10 < 1.5 < f(3)=26

    f(0)=-10 < 0.75 < f(1.5)=5.75

    f(0.75)=-2.6875 < 1.125 < f(1.5)=5.75

    f(0.75)=-2.6875 < 0.9375 < f(1.125)=1.390625

    f(0.9375)=-0.68359375 < 1.03125 < f(1.125)=1.390625

    f(0.9375)=-0.68359375 < 0.984375 < f(1.03125)=0.344726563

    f(0.984375)=-0.171630859 < 1.0078125 < f(1.03125)=0.344726563

    f(0.984375)=-0.171630859 < 0.99609375 < f(1.0078125)=0.085998535

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