Bisection Method for quadratic?

Question

! want to do a bisection method for the quadratic (x-1)(x+10)

but the problem is, what two possible numbers and its midpoint

should i used to make a start so that i can get a correct answer??

Answer 1

Favorite Answer

you need two values that have opposite signs. just try some values:

how about x=0 and x=3

f(0)=-10 < 1.5 < f(3)=26

f(0)=-10 < 0.75 < f(1.5)=5.75

f(0.75)=-2.6875 < 1.125 < f(1.5)=5.75

f(0.75)=-2.6875 < 0.9375 < f(1.125)=1.390625

f(0.9375)=-0.68359375 < 1.03125 < f(1.125)=1.390625

f(0.9375)=-0.68359375 < 0.984375 < f(1.03125)=0.344726563

f(0.984375)=-0.171630859 < 1.0078125 < f(1.03125)=0.344726563

f(0.984375)=-0.171630859 < 0.99609375 < f(1.0078125)=0.085998535