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Question

a submarine stays at 150 m below water surface . it first ascends vertically to a position of 42 m below water surface and then descends vertically to a position of 135 m below the water surface . if -60 denotes 60 m the water surface , find the total distance travelled by submarine?

Answer 1

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It first ascends vertically to a position of 42 m below water surface :

- 42 - (- 150) = 108 m travelled.

And then descends vertically to a position of 135 m below the water surface :

- 42 - (- 135) = 93 m travelled.

∴ The total distance travelled by submarine = 108 + 93 = 201 m.