A nonuniform beam 4.44 long and weighing 1.01 makes an angle of 25.0 below the horizontal. It is held in posit?

A nonuniform beam 4.44m long and weighing 1.01kN makes an angle of 25.0 degree below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 3.10m farther down the beam and perpendicular to it (see the figure )

http://session.masteringphysics.com/problemAsset/1...

The centre of gravity of the beam is 1.98m down the beam from the pivot. Lighting equipment exerts a 4.92kN downward force on the lower left end of the beam.

Part A

Find the tension in the cable.

Part B

Find the vertical component of the force exerted on the beam by the pivot.

Assume that the positive x and y axes are directed to the right and upward respectively.

Part C

Find the horizontal component of the force exerted on the beam by the pivot.

Assume that the positive x and y axes are directed to the right and upward respectively.

1 Answer

Relevance
Still have questions? Get your answers by asking now.