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# MQ32 --- Logarithm

Difficulty: 25%Simplify - logᵤv.

Update:

NO...

Update 2:

Note that there's a minus sign before logᵤv.

Update 3:

Sorry, I would like to change the question to:

Simplify log⁻¹ᵤv.

Update 4:

Note that log⁻¹ᵤv = (logᵤv)⁻¹.

### 2 Answers

Rating

- 8 years agoFavorite Answer
我想問u同v有冇關係???

2012-07-23 15:13:47 補充：

-log_u(v) = log_u(1/v) or log_(1/u)(v)

2012-07-23 20:57:18 補充：

http://latex.codecogs.com/gif.latex?\begin{align*}...

log⁻¹ᵤv = u^v

2012-07-25 22:31:57 補充：

sorry= =

\begin{align*}

(log_uv)^{-1} &=\frac{1}{log_uv} \\

&= \frac{logu}{logv}\\

&= log_vu\\

\end{align*}

log⁻¹ᵤv = log_v(u)

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