MQ32 --- Logarithm

Difficulty: 25%Simplify - logᵤv.

Update:

NO...

Update 2:

Note that there's a minus sign before logᵤv.

Update 3:

Sorry, I would like to change the question to:

Simplify log⁻¹ᵤv.

Update 4:

Note that log⁻¹ᵤv = (logᵤv)⁻¹.

2 Answers

Rating
  • 8 years ago
    Favorite Answer

    我想問u同v有冇關係???

    2012-07-23 15:13:47 補充:

    -log_u(v) = log_u(1/v) or log_(1/u)(v)

    2012-07-23 20:57:18 補充:

    http://latex.codecogs.com/gif.latex?\begin{align*}...

    log⁻¹ᵤv = u^v

    2012-07-25 22:31:57 補充:

    sorry= =

    \begin{align*}

    (log_uv)^{-1} &=\frac{1}{log_uv} \\

    &= \frac{logu}{logv}\\

    &= log_vu\\

    \end{align*}

    log⁻¹ᵤv = log_v(u)

    Source(s): me
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  • 8 years ago

    cannot see

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