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Question

A ball is thrown vertically into the air and when it returns after an interval of 2 seconds, it is caught. What is the acceleration of the ball after leaving the hand?

Can someone please explain how to do this question?

Answer 1

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U don't actually "do" the question since it takes no calculation.

Rather U *know* answer from the fact that any object thrown into the air

experiences what's called "Free-Fall"

{this assume's UR taking 1st year physics}

Free-Fall is defined to be any time an object is moving in the air on its own

{not connected to anything}

and air friction is ignored.

This means that Free-Fall is when an object moving in the air has only ONE acceleration acting on it. That is, the acceleration of gravity = g.

so assuming the ball in UR question is in Free-Fall - the answer by definition = g

Answer 2

All of the details are irrelevant. Once the ball is no longer being pushed by the hand, it is subject to the acceleration of gravity, only, because you are also ignoring air resistance. And it is not attached to a rubber band, nor influenced by a magnetic or electric field, etc.

Answer 3

the acceleration is 69

Source(s): 50 Shades of grey

Answer 4

a = (v - v0)/t