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Need help with a physics problem?

A ball is thrown vertically into the air and when it returns after an interval of 2 seconds, it is caught. What is the acceleration of the ball after leaving the hand?

Can someone please explain how to do this question?

4 Answers

  • ?
    Lv 7
    9 years ago
    Favorite Answer

    U don't actually "do" the question since it takes no calculation.

    Rather U *know* answer from the fact that any object thrown into the air

    experiences what's called "Free-Fall"

    {this assume's UR taking 1st year physics}

    Free-Fall is defined to be any time an object is moving in the air on its own

    {not connected to anything}

    and air friction is ignored.

    This means that Free-Fall is when an object moving in the air has only ONE acceleration acting on it. That is, the acceleration of gravity = g.

    so assuming the ball in UR question is in Free-Fall - the answer by definition = g

  • Nicky
    Lv 5
    9 years ago

    All of the details are irrelevant. Once the ball is no longer being pushed by the hand, it is subject to the acceleration of gravity, only, because you are also ignoring air resistance. And it is not attached to a rubber band, nor influenced by a magnetic or electric field, etc.

  • 9 years ago

    the acceleration is 69

    Source(s): 50 Shades of grey
  • Anonymous
    9 years ago

    a = (v - v0)/t

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