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# homework help plz [(y^2-64)/y] divided by [(y+8)/(y+6)] DIVIDE AND SIMPLIFY?

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- 9 years agoFavorite Answer
[ ( y^2 - 64 ) / y ] / [ ( y + 8 ) / ( y + 6 ) ]

= [ ( y^2 - 64 ) / y ] * [ ( y + 6 ) / ( y + 8 ) ]

= [ ( y - 8 ) ( y + 8 ) / y ] * [ ( y + 6 ) / ( y +8 ) ]

= ( y - 8 ) ( y + 6 ) / y

= (y^2 - 2y - 48) / y

= ( y^2 -8y + 6y - 48) / y

= ( y +6 ) (y - 8) /y

- alabasterLv 59 years ago
[(y^2-64)/y] / [(y+8)/(y+6)]

= [(y^2-64)/y] * [(y+6)/(y+8)]

= [(y-8)(y+8)/y] * [(y+6)/(y+8)]

= (y-8)(y+6)/y

= (y^2 - 2y - 48)/y

= y - 2 - 48/y

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