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# Help me plz math again?

Given three consecutive odd numbers such that the square of the second number is 192 less that the square of the third number. Find those numbers.

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- notthejakeLv 79 years agoFavorite Answer
let n be the middle number

the bigger number will be n + 2 and the smaller will be n - 2

n^2 + 192 = (n + 2)^2

n^2 + 192 = n^2 + 4n + 4

188 = 4n

n = 47 (the middle number)

so the three numbers are 45 , 47 , and 49

check: 47^2 = 2209

49^2 = 2401

2401 - 2209 = 192 check

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