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# Trigonometry Help Please?

cosx sinx + sinx = 0, 0° ≤ x < 360°

### 2 Answers

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- ?Lv 49 years agoFavorite Answer
factorise the sin x out.

sin x (cos x + 1) = 0

Pretend that sin x and cos x are x and y, and solve like a normal equation.

sin x = 0, cos x = -1

When sin x = 0,

x = 0, 180

When cos x = -1,

x = 180, 180

Therefore x = 0, 180.

- mohanrao dLv 79 years ago
cos(x) sin(x) + sin(x) = 0

=> sin(x) [ 1 + cos x ] = 0

sin x = 0 and cos x = -1

x = 0, 180 and 180

x = 0° and 180° in the interval 0° ≤ x < 360°

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