Anonymous
Anonymous asked in Science & MathematicsMathematics · 9 years ago

Trigonometry Help Please?

cosx sinx + sinx = 0, 0° ≤ x < 360°

2 Answers

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  • ?
    Lv 4
    9 years ago
    Favorite Answer

    factorise the sin x out.

    sin x (cos x + 1) = 0

    Pretend that sin x and cos x are x and y, and solve like a normal equation.

    sin x = 0, cos x = -1

    When sin x = 0,

    x = 0, 180

    When cos x = -1,

    x = 180, 180

    Therefore x = 0, 180.

  • 9 years ago

    cos(x) sin(x) + sin(x) = 0

    => sin(x) [ 1 + cos x ] = 0

    sin x = 0 and cos x = -1

    x = 0, 180 and 180

    x = 0° and 180° in the interval 0° ≤ x < 360°

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