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# Traveling at a speed of 17.7 m/s, the driver of an automobile suddenly locks the wheels by slamming on the?

brakes. The coefficient of kinetic friction between the tires and the road is 0.660. What is the speed of the automobile after 1.70 s have elapsed? Ignore the effects of air resistance.

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- TechnobuffLv 79 years agoFavorite Answer
(9.8 x 0.66) = friction of 6.468N. per kg.

Acceleration = (f/m) = 6.468/1, = -6.486m/sec^2.

Change in velocity = (at) = 6.486 x 1.7, = 11.0262m/sec.

(17.7 - 11.0262) = 6.674m/sec.

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