Traveling at a speed of 17.7 m/s, the driver of an automobile suddenly locks the wheels by slamming on the?

brakes. The coefficient of kinetic friction between the tires and the road is 0.660. What is the speed of the automobile after 1.70 s have elapsed? Ignore the effects of air resistance.

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  • 9 years ago
    Favorite Answer

    (9.8 x 0.66) = friction of 6.468N. per kg.

    Acceleration = (f/m) = 6.468/1, = -6.486m/sec^2.

    Change in velocity = (at) = 6.486 x 1.7, = 11.0262m/sec.

    (17.7 - 11.0262) = 6.674m/sec.

  • 9 years ago

    Vf=Vi+(at)

    17.7+(-0.66x1.7)=16.578 m/s (?)

    Technobuff is right.

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