Math problem with circles?
Here's the question: The bull's-eye of the dartboard shown (in the link, it's red) has a diameter of 10cm. The width of each ring is 5 cm. If a random toss hits the target, what is the probability that it hits the bull's-eye?
Here's a picture of what the dart board kind of looks like (it's 3 ringed)
- jsjsLv 59 years agoFavorite Answer
The dartboard has a radius of 15 cm, so its area is Pi * (15 cm)^2.
The bull's-eye has a radius of 5 cm, so its area is Pi * (5 cm)^2.
Hence the probability is
[Pi * (5 cm)^2]/[Pi * (15 cm)^2.] = (5/15)^2 = (1/3)^2 = 1/9.
- 9 years ago
The entire dartboard has a radius of 15cm. So, find the ratio of the area of the bullseye compared to the radius of the dartboard
(pi * 5^2) / (pi * 15^2) =>
25 / 225 =>
- anonimousLv 69 years ago
The radius of the target is 15 cm
The radius of the bull's eye is 5 cm
The area of the entire target is 9 times the area of the bull's eye
The area of the target excluding the bull's eye is therefore 8 times the area of the Bull's eye
If a random toss hits the target, the probability that it hits the bull's-eye is:
The odds are 8 to 1 that the random hit of the target will miss the bull's eye