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# Math problem with circles?

Here's the question: The bull's-eye of the dartboard shown (in the link, it's red) has a diameter of 10cm. The width of each ring is 5 cm. If a random toss hits the target, what is the probability that it hits the bull's-eye?

Here's a picture of what the dart board kind of looks like (it's 3 ringed)

### 3 Answers

- jsjsLv 59 years agoFavorite Answer
The dartboard has a radius of 15 cm, so its area is Pi * (15 cm)^2.

The bull's-eye has a radius of 5 cm, so its area is Pi * (5 cm)^2.

Hence the probability is

[Pi * (5 cm)^2]/[Pi * (15 cm)^2.] = (5/15)^2 = (1/3)^2 = 1/9.

- 9 years ago
The entire dartboard has a radius of 15cm. So, find the ratio of the area of the bullseye compared to the radius of the dartboard

(pi * 5^2) / (pi * 15^2) =>

25 / 225 =>

1/9

1-in-9

- anonimousLv 69 years ago
The radius of the target is 15 cm

The radius of the bull's eye is 5 cm

The area of the entire target is 9 times the area of the bull's eye

The area of the target excluding the bull's eye is therefore 8 times the area of the Bull's eye

If a random toss hits the target, the probability that it hits the bull's-eye is:

1/9=0.111...

The odds are 8 to 1 that the random hit of the target will miss the bull's eye

.