Anonymous
Anonymous asked in Science & MathematicsChemistry · 9 years ago

What is the pH of a solution that is formed by diluiting 450 mL of 0.045 molar NaOH with 300 mL of water?

Assume volumes of liquids are additive.

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  • 9 years ago
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    Calculate the molarity of the final solution:

    M1V1 = M2V2

    M1* 750 = 0.045*450

    M1 = 20.25/750

    M1 = 0.027M

    [OH-] = 0.027M

    Equation:

    [H+][OH-] = 10^-14

    [H+] = 10^-14/[OH-]

    [H+] = 10^-14/ 0.027

    [H+] = 3.70*10^-13

    pH = -log [H+]

    pH = -log (3.70*10^-13)

    pH = 12.43

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