# Easy Hardy Weinberg Question?

Hey i have all the numbers but im not sure how the second question is done

The ability to taste PTC is due to a single dominate allele "T". You sampled 215 individuals in biology, and determined that 150 could detect the bitter taste of PTC and 65 could not. Calculate all of the potential frequencies.

If there are 970 people, how many would you expect to be non-tasters?

tt=0.00302

t=0.55

T=0.45

TT=0.2025

Tt=0.495

im not sure how question 2 can be done,

If there are 970 people, how many would you expect to be non-tasters?

If anyone can help i can give you a quick 10 points!

Update:

thanks jacob, thats what I was thinking but i wasnt sure

Update 2:

wait, wouldnt it be 0.00302 * 970?

Update 3:

i just found out that i made a mistake,

0.00302 should be 0.3023,

Relevance
• Anonymous
8 years ago

Actually, since you know that q=.55 and p=.45, you can calculate that p^2=.2, q^2=.3, 2pq=.5. So, to figure your percentages out of 970 people, it would be:

(970*.5)+(970*.2)=679. You can check this by multiplying 970*.3=291. 291+679=970. So, there would be 679 tasters out of 970 people. You can't just multiply 970 by .45 because .45 is only the percentage of the dominant allele. Since dominant phenotypes are expressed by homozygous dominant and heterozygous genotypes you have use .45 and .55 to calculate the number of individuals with these genotypes and then add them together.

And I'm a Biology major.

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• Anonymous
8 years ago

Since now all you need is the number of people who can taste it:

45 % carry the trait to taste PTC. Multiply .45 by 970 and you should have the correct answer.

Source(s): Bio student
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