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The coordinates of the turning point of the graph of the equation y=2x^2-4x+6 are (1,k). what is the value of?

k?

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  • 8 years ago
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    since (1,k) is a point on the graph of this equation, all you have to do is plug 1 in for x, and when you find y, you've found k.

    y = 2(1)^2 - 4(1) + 6 = 2 - 4 + 6 = 4

    k = 4

    that's it! ;)

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  • 8 years ago

    Just sub in x=1 into your equation and it will tell you what y is, y being k in this case. 2x^2 = 2. -4x = -4. So k (y) equals 4.

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