The coordinates of the turning point of the graph of the equation y=2x^2-4x+6 are (1,k). what is the value of?
- Marley KLv 78 years agoFavorite Answer
since (1,k) is a point on the graph of this equation, all you have to do is plug 1 in for x, and when you find y, you've found k.
y = 2(1)^2 - 4(1) + 6 = 2 - 4 + 6 = 4
k = 4
that's it! ;)
- 8 years ago
Just sub in x=1 into your equation and it will tell you what y is, y being k in this case. 2x^2 = 2. -4x = -4. So k (y) equals 4.