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A particle of mass m1 = 2.8 kg moving along the x axis collides with a particle of mass m2 = 4.3 kg?

A particle of mass m1 = 2.8 kg moving along the x axis collides with a particle of mass m2 = 4.3 kg initially at rest. The incoming particle is deflected in the direction 27 degrees above the x axis, whereas the target particle moves off at 11 m/s at 36 degrees below the x axis. What are the initial and final speeds of the 2.8 kg particle?

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  • Ben
    Lv 4
    9 years ago
    Favorite Answer

    The final speed is found just using the conservation of momentum theory:

    11*4.3 = 2.8*x

    x= (11*4.3)/2.8

    x being the final velocity

    EDIT: I am back and was bored so I gave it a go, initial velocity:

    ((11*4.3)/2.8) cos (27) = Initial Velocity.

  • 4 years ago

    relies upon on situation. Like time i choose sluggish and issues that would desire to be dealt with a a sluggish %. and to make issues final. yet for different issues like making use of for occasion i could choose quickly, or some thing I dislike, or some thing that desires to be accomplished with out postpone. So it relies upon on the situation.

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