I Need Help With This Geometry Problem!?!?
Triangle JKL is inscribed in Circle P with Diameter JK and the measure of Arc JL equal to 130 degrees. Find the measure of Angle KJL.
- JasonLv 48 years agoFavorite Answer
This probably has to do with the fact that a triangle inscribed in a semicircle is always a right triangle (so angle JLK is 90) but I want to make sure I understand this right first...where is JL subtending a 130 degree angle? At K? At the center of the circle?
- ironduke8159Lv 78 years ago
arc KL = 180 - 130 = 50 degrees
So inscribed angle KJL = 1/2 arc KL = 1/2 (50) = 25 degrees