I Need Help With This Geometry Problem!?!?

Triangle JKL is inscribed in Circle P with Diameter JK and the measure of Arc JL equal to 130 degrees. Find the measure of Angle KJL.

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  • Jason
    Lv 4
    8 years ago
    Best Answer

    This probably has to do with the fact that a triangle inscribed in a semicircle is always a right triangle (so angle JLK is 90) but I want to make sure I understand this right first...where is JL subtending a 130 degree angle? At K? At the center of the circle?

  • 8 years ago

    arc KL = 180 - 130 = 50 degrees

    So inscribed angle KJL = 1/2 arc KL = 1/2 (50) = 25 degrees

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