how would you answer this cos(x)sin^4(x)?

Im trying to use the formulas for lowering powers to write in first degree of cosine.

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  • 9 years ago
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    cos(x)*sin^4(x) = cos(x)*[sin^2(x)]^2 = cos(x)* [(1-cos(2x))/2]^2 =

    = cos(x)* 1/4 * (1 - 2*cos(2x) + cos^2(2x)) = 1/4*cos(x)*(1 - 2*cos(2x) + (1+cos4x)/2)

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