More Algebra help :(?

Find an equation of the line containing the given pair of points.

(-5,-3) & (-9,-4)

The equation of the line in slope intercept form form is y=?

Thanks in advance for any help!

It's been too long since I've done this stuff.

3 Answers

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  • Mike G
    Lv 7
    9 years ago
    Favorite Answer

    slope = (-4- - 3)/(-9- -5) = -1/-4 = 1/4

    y+3=(1/4)(x+5)

    4y+12=x+5

    4y = x - 7

    y = x/4 - 7/4

  • Anonymous
    9 years ago

    Okay first we find the slope.

    It's rise over run:

    Δy/Δx= (-3+4)/(-5+9)=1/4

    Now that you have the slope, you should know that we can write the equation of a line with its slope and a given point of (x1,y1):

    y-y1=m(x-x1):

    y+3=1/4(x+5)

    y=(x-7)/4

  • 9 years ago

    y=mx + b, m is the slope, b is the y intercept.

    slope = (y2-y1) / (x2-x1)

    m= (-1--7)/(-9--5)

    m=(6/-4)

    m = -1.5

    so we have y=-1.5x + b.

    Substitute x and y to get b.

    -1 = -1.5*-9 +b

    -1 = 13.5 +b

    b=-14.5

    so, y = -1.5x -14.5

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