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# More Algebra help :(?

Find an equation of the line containing the given pair of points.

(-5,-3) & (-9,-4)

The equation of the line in slope intercept form form is y=?

Thanks in advance for any help!

It's been too long since I've done this stuff.

### 3 Answers

- Mike GLv 79 years agoFavorite Answer
slope = (-4- - 3)/(-9- -5) = -1/-4 = 1/4

y+3=(1/4)(x+5)

4y+12=x+5

4y = x - 7

y = x/4 - 7/4

- Anonymous9 years ago
Okay first we find the slope.

It's rise over run:

Δy/Δx= (-3+4)/(-5+9)=1/4

Now that you have the slope, you should know that we can write the equation of a line with its slope and a given point of (x1,y1):

y-y1=m(x-x1):

y+3=1/4(x+5)

y=(x-7)/4

- 9 years ago
y=mx + b, m is the slope, b is the y intercept.

slope = (y2-y1) / (x2-x1)

m= (-1--7)/(-9--5)

m=(6/-4)

m = -1.5

so we have y=-1.5x + b.

Substitute x and y to get b.

-1 = -1.5*-9 +b

-1 = 13.5 +b

b=-14.5

so, y = -1.5x -14.5