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# Chemistry gas law help?

I need help with this: An 805 mL sample of gas is collected at 382 mm Hg and 273C . what volume would the sample occupy at stp? And can you please put a step by step how to do it so i can understand it please and thankyou.

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- Lexi RLv 79 years agoFavorite Answer
STP is standard temperature and pressure, which is 0 deg celcius (273 Kelvin) and 1 atm (760 mmHg)

Use the combined gas equation

P1V1 / T1 = P2V2 / T2

P1 = initial pressure = 382 mmHg

V1 = initial volume = 805 ml

T1 = initial temp = 273 deg C = 273 deg C + 273 = 546 K

P2 = final pressure = 760 mmHg

V2 = final volume = ? ml

T2 = final temperature = 273 K

solve for V2

V2 = P1V1T2 / (P2T1)

= 382 mmHg x 805 ml x 273 K / (760 mmHg x 546 K)

= 202 ml

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