this is old school - so put your seat belt on

50-8a^2=0

subtract 50 from both sides (keeps it an equation)

-8A^2 = -50

add 8A^2 to both sides

0 = 8A^2 - 50

this equation is like A + B + C

except B i ZERO and non existent

Factor A = 1.8 and 2,4

Factor C = 1,50 and 2,25 and 5,10

now since we have a - for C

that means we will have a + and a - in our solution

SO - what combination for the factors of A and C

are EQUAL - so when subtracted from one another = 0

2 x 10 and 4 x 5

yep I got those two, too

so that

(2A - 5) (4A +10)

orrrrrrrrrrrrrrrrrr

(2A + 5)(4A - 10)

two solutions

PIZZA TIME

all the best

Source(s):
extra cheese and pepperoni please

after my first slice - I rethought it out - -

your teacher may want to have

(5 - 2A)(10 +4A)

or

(5 + 2A)(10 - 4A)

you can see how we just swapped that around - pass the parmesian please?