Three 15 microF capacitors are connected in series with each other between the terminals of a 10 V battery.?

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Determine the equivalent capacitance of the series combination.
Best Answer
  • TomV answered 2 years ago
1/Ce = 1/C1 + 1/C2 + 1/C3 = 3/C
Ce = C/3 = 15/3 = 5 μF

http://farside.ph.utexas.edu/teaching/30...
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Other Answers (1)

  • Daiii answered 2 years ago
    For capacitors in series, the total capacitance is the reciprocal of the sum of the reciprocals

    1 / ( 1/15 + 1/15 + 1/15 ) = 5 microFarads

    Of course, for N equal valued caps in series, this simply reduces to (1/N) times the individual value.
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