need help with some math problems.?
1. 5x /25
4. 3x^2 - 9x /12x^2
- Yummy cookiesLv 49 years ago
I'm guessing you have to simplify the expressions?
1.| 5x /25
You get an expression that equals another one by dividing both numerator and denominator with any non-zero expression.
5 is a prime number, only divisible by 1 and 5. If you divide the numerator (5x) and denominator (25) by 1, you get the same expression. Only 5 is left... 5x/25 equals x/5
2 is divisible by 1 and by 2. So 12y^2/2y = 6y^2/y.
y^2/y equals y, so So 6y^2/y=6y
15 is divisible by 1, 3 and 5. 18 is divisible by 1, 2 and 3. So we can divide numerator and denominator both by 3 and get a simpler and an equal expression: 18x^2/15xy^4=6x^2/5xy^4
x^2/x=x, so 6x^2/5xy^4=6x/5y^4
4.| 3x^2 - 9x /12x^2
If you meant (3x^2 - 9x) /12x^2 (where both 3x^2 and 9x are the numerator), than you get (3x^2 - 9x) /12x^2 equals (x-3)/4x
But if you meant what you wrote: 3x^2 - 9x /12x^2. Than you get 3x^2 - 9x /12x^2=3x^2 - 3/4x
(I hope you know why. If you don't, you ask for an explanation so you can solve it on test when it really matters.)
The numerator and the denominator have the same expression (x-8) by which they are multiplied. Let's divide both by (x-8): x^2(x-8)/x(x-8)=x^2/x
We already know x^2/x=x
- 9 years ago
answers are as follows
4. 3x^2 - 3/(4x)