is the domain for f(x) = 1/2(x+3) all real numbers?
the 3 is in the numerator - it's (1/2)(x+3) - so, it's all real, correct?
- Randy PLv 79 years agoFavorite Answer
Depends on whether that (x + 3) is in the numerator or the denominator.
If it's in the numerator, yes.
If it's in the denominator, no. You can't divide by 0, and there is a real number which makes x + 3 equal to 0.
- Eclipse-girlLv 79 years ago
No. x cannot equal - 3. then the denominator would equal zero.
Whenever you deal with fractions, you can't have the denominator ever equal zero
so the domain is (- infinity, -3) U (-3, infinity)
The round parentheses indicate everything up to but not including that value, kind of like a < or > symbol. A square bracket [ or ] indicates the the value is included.
We use round parenthesis for infinity because of convention. We never get to infinity, there is always more out there.
In this example, -3 in not included.
- Anonymous9 years ago
no -3 is not in the domain